An object is solid throughout. when the object is completely submerged in ethyl alcohol, its apparent weight is 16.5 n. when completely submerged in water, its apparent weight is 13.3 n. what is the volume of the object?

V = 1.7 x 10^{-3} m^{3}

Explanation:

apparent weight in ethyl alcohol = 16.5 N

apparent weight in water = 13.3 N

apparent weight = mg - ρgV

where

m = mass

g = acceleration due to gravity = 9.8 m/s^{2}

ρ = density

V = volume

    we can solve the two equations above as simultaneous equations by subtracting equation 2 from equation 1

we have

16.5 - 13.3 = (mg - mg) - ρ₁gV - (-ρ₂gV)

3.2 = gV(ρ₂ - ρ₁)

V = \frac{3.2}{g(ρ₂-ρ₁)}

where

ρ₂ = density of water = 1000 kg/m^{3}

ρ₁ = density of ethyl alcohol = 806 kg/m^{3}

V = \frac{3.2}{9.8(1000 - 806)}

V = 1.7 x 10^{-3} m^{3}

it should be -8.6 cm hope this out

force tends to be low and long diustance masses are high