The average human has a density of 945 kg/m3 after inhaling and 1020 kg/m3 after exhaling. (a) without making any swimming movements, what percentage of the human body would be above the surface in the dead sea (a body of water with a density of about 1230 kg/m3) in each of these cases?

20% of the human body float above the surface in the dead sea.

Explanation:

Given data,

The human density after inhaling, d₁ = 945 kg/m³

The human density after exhaling, d₂ = 1020 kg/m³

Therefore the average human density, d = 982.5 kg/m³

The density of the dead sea, D = 1230 kg/m³

The percentage of density of human body to the dead sea is,

                                   P % = (982.5 / 1230) x 100 %

                                           = 80 %

Therefore, the human body has 80% of dead sea density.

Hence, 20% of the human body float above the surface in the dead sea.

laticia draws the diagram below to show earth’s magnetic field.

answer

the arrows to the right of earth should point up.

a.   mass number from atomic number