Aball is thrown upward from the top of a building 160 ft high with an initial velocity of 64 ft/sec. its height in feet above the ground is given by s(t)=−16t2+64t+160 where t
is in seconds.
a) when does the ball reach its maximum height?
b) what is its maximum height?
c) when does it hit the ground?
d) with what velocity does it hit the ground?
e) what was its acceleration at time t=1?

2 seconds

5.74165 seconds

-32 ft/s²

119.73 ft/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 32 ft/s²

The maximum height will be reached in 2 seconds

From the given equation

The maximum height is 224 ft from the ground

Time taken to fall from the maximum height is 3.74165 seconds

Time taken from the point in time the ball is thrown is 2+3.74165=5.74165 seconds

Velocity with which the ball will hit the ground is 119.73 ft/s

At t = 1

Acceleration of a body thrown is always i.e., a body in free fall is always 32 ft/s². Here as the ball is thrown up the it will be negative so -32 ft/s²

that tool is called an altimeter which measures your altitude which can be used to tell which atmosphere you are currently in, including the stratosphere.

hope this ! : )

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.