A1.5-cm object is placed 0.50 m to the left of a diverging lens with a focal length of 0.20 m. a converging lens with a focal length of 0.17 m is located 0.08 m to the right of the diverging lens. what is the height and orientation with respect to the original object of the final image?

The object for the converging lens is upright and 0.429 cm tall, the image of this converging lens is inverted and 1.375 cm high

Explanation:

Let

For diverging lens:

Magnification =

Image height (negative sign means the image is virtual, inverted.

This image is meter to left of the center of the diverging lens.

The converging lens is located 0.08 m to the right of the diverging lens

The distance between the image of the diverging lens and center of the converging lens =

The image of the diverging lens becomes the object of the converging lens.

magnityde and direction