(a) what is the length of a simple pendulum that oscillates with a period of 3.2 s on earth, where the acceleration due to gravity is 9.80 m/s2, and on mars, where the acceleration due to gravity is 3.70 m/s2?

length (earth)=?

length (mars)=?

(b) what mass would you need to suspend from a spring with a force constant of 20 n/m in order for the mass-spring system to oscillate with a period of 3.2 s on earth, where the acceleration due to gravity is 9.80 m/s2, and on mars, where the acceleration due to gravity is 3.70 m/s2?

mass (earth)=?

mass (mars)=?

Explanation:

The expression relating length and time period

T  = 2π

3.2 =

l = 2.54 m

On Mars g = 3.7

L = .96 m

b )

Expression for elastic constant and time  period is as follows

m = 5.19 N/s

Time period of oscillation due to spring is not dependent on g , so same time period will be found on Mars as that on the earth.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz