Awheel is spinning about its axle such that the wheel rotates by 2π radians (1 rev) every 0.43 s. while the wheel spins, the axle is tilted through an angle of π/2 radians (90°) in a time of 0.30 s. the magnitude of the angular momentum changes by 50.00 kg m2/s when the axle is tilted. what is the magnitude of the torque applied to the wheel in order to tilt the axle by 90°?

 τ = 166.67 N m

Explanation:

The torque is related to the angular momentum

        τ = dL / dt

Bold indicates vectors, where tau is the torque and L is the angular momentum

In this case we put the variations, It's like looking for middle values

      τ = ΔL / Δt

Let's calculate

     τ = 50.00 / 0.30

     τ = 166.67 N m

Applied in the direction of rotation at the end of the wheel

answer is c

explanation:

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