A5.0 g coin is placed 15 cm from the center of a turntable. the coin has static and kinetic coefficients of friction with the turntable surface of μs = 0.70 and μk = 0.50. the turntable very slowly speeds up.

Angular speed will reach 6.833rad/s before the coin starts slipping

Explanation:

There is no question but I'll asume the common one: Calculate the speed of the turntable before the coin starts slipping.

With a sum of forces:

At this point, friction force is maximum, so:

Solving for V:

V=1.025 m/s

The angular speed of the turntable will be:

ω = V/R = 6.833 rad/s   This is the maximum speed it can reach before the coin starts slipping.

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2