You wish to boil 1.9 kg of water, which has a specific heat capacity of 4186 j/kg-k. the water is initially at room temperature (293 k). water boils at 373 k.
1) how much energy must be added to the water by heating it in order for it to start boiling?

6.36 105 J

Explanation:

In calorimetry all the energy given to a system is converted to heat and the equation for heat is

     Q = m   ΔT

The temperature can be in degrees Celsius or Kelvin since the interval between them is the same, substitute and calculate

Q = 1.9 4186 (373-293)  

Q = 6.36 105 J  

This heat equals the energy supplied

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

its c i just checked it