Suppose the earth's magnetic field at the equator has magnitude 0.5 t and a northerly direction at all points. how fast must a singly ionized uranium atom (m=238u, q=e) move so as to circle the earth 1.44 km above the equator? give your answer in meters/second.

Velocity will be

Explanation:

We have given magnetic field B = 0.00005 T

Mass m = 238 U

We know that

So 238 U

Radius

We know that magnetic force is given by

which is equal to the centripetal force

So

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .

a.) travels faster in solids because the particles are closer together.

air is a gas water is a liquid