Assume that the speed of light in a vacuum has the hypothetical value of 7.58 m/s. in a pickup baseball game, a runner runs at a constant velocity from third base to home plate in a time of 2.50 s, according to the runner. also according to the runner, the distance covered is 15.0 m. what is the distance covered, according to the catcher who is standing at home plate?

To solve this problem it is necessary to apply the concepts related to relativity.

The distance traveled by the light and analyzed from an observer relative to it is established as

Where,

L = Length

c = Speed of light (7.58m/s at this case)

v = Velocity

Our velocity can be reached by kinematic motion equation, where

Here,

d = Distance

t = Time

Replacing

Replacing at the previous equation,

Therefore the distance covered, according to the catcher who is standing at home plate is 24.5461m

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.