Expressed in cylindrical coords. use the analogy among the equations that determine vector potential and magnetic field: ∇"⃗ ∙ �"⃗ = 0 ∇"⃗ × �"⃗ = �)�⃗ �⃗ = 0 ∇"⃗ × �⃗ = �"⃗ to find the vector potential: a) for � ≤ � b) for � >

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.