A545-kg satellite is in a circular orbit about earth at a height above earth equal to earth's mean radius. (a) find the satellite's orbital speed.(b) find the period of its revolution. (c) find the gravitational force acting on it.

Answer

given,

mass of satellite = 545 Kg

R = 6.4 x 10⁶ m

H = 2 x 6.4 x 10⁶ m

Mass of earth = 5.972 x 10²⁴ Kg

height above earth is equal to earth's mean radius

a) satellite's orbital velocity

   centripetal force acting on satellite =

     gravitational force =

    equating both the above equation

          v = 5578.5 m/s

b)

          T = 14416.92 s

          T = 4 hr

c) gravitational force acting

     F = 5202 N

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