A240 g toy car is placed on a narrow 60-cm-diameter track with wheel grooves that keep the car going in a circle. the 1.0 kg track is free to turn on a frictionless, vertical axis. the spokes have negligible mass. after the car's switch is turned on, it soon reaches a steady speed of 0.79 m/s relative to the track. what then is the track's angular velocity, in rpm?

The track's angular velocity is W2 = 4.15 in rpm

Explanation:

Momentum angular can be find

I = m*r^2

P = I*W

So to use the conservation

P1 + P2 = 0

I1*W1 + I2*W2 = 0

Solve to w2 to find the angular velocity

0.240kg*0.30m^2*0.79m/s=-1kg*0.30m^2*W2

W2 = 0.435 rad/s

W2 = 4.15 rpm

weather forecasts are done by collecting data about the current state of the atmosphere mainly the temperature, humidity and wind and using meteorology, to determine the atmosphere that evolves over time. the h and l mean the high and low pressure. the red strip is a warm front. the blue strip is a cold front. the blue and red strip is a stationary front. the purple strip is a occluded front.

explanation:

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