72.0-kg person pushes on a small doorknob with a force of 5.00 n perpendicular to the surface of the door. the doorknob is located 0.800 m from axis of the frictionless hinges of the door. the door begins to rotate with an angular acceleration of 2.00 rad/s2. what is the moment of inertia of the door about the hinges?

Explanation:

Given

mass

Force

door knob is located at a distance of r=0.8 m from axis

Angular acceleration of door

Torque

where I=moment of inertia

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explanation:

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