Gibbons, small asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. a 8.6 kg gibbon has an arm length (hand to shoulder) of 0.60 m. we can model its motion as that of a point mass swinging at the end of a 0.60-m-long, massless rod. at the lowest point of its swing, the gibbon is moving at 3.5 m/s .what upward force must a branch provide to support the swinging gibbon? express your answer to two significant figures and include the appropriate units.(textbook is college physics by: knight, jones, and field.)

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

the answer is b i think