Acord is wrapped around the rim of a solid uniform wheel 0.280m in radius and of mass 8.80kg. a steady horizontal pull of 32n to the right is exerted on the cord, pulling it off tangentially from the wheel. the wheel is mounted on frictionless bearings on a horizontal axle through its center. what is the wheels angular acceleration? what force does the axle apply to the wheel? what torque does the axle apply to the wheel?

Explanation:

Given

radius of wheel

mass of wheel

Force

Moment of Inertia of solid wheel

Torque is given by

Force on the axle is 32 N since there is no linear acceleration of the system

using Third law F=32 N

Torque of the axle applied to the wheel is zero because force of axle imparted at the center of axle

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge