Aflat uniform film with an index of refraction n2=1.22 is grown on top of a flat diamond. a light ray enters from the air above the film with an angle of incidence 72. what is the angle of refraction of the light ray once the ray has passed through the film layer and into the diamond?

in the film medium

in diamond medium

Explanation:

Given:

According to the Snell's Law:

where:

refractive index of air ≈ 1

is the angle of incident on the film in (medium 1) air

is the angle of refraction in the (medium 2) film

Using Snell's law:

Now this angle will be the angle of incident for diamond.

∴Angle of refraction in diamond medium after passing through film-diamond interface:

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow