A2.4-m high 200-m2 house is maintained at 22â°c by an air-conditioning system whose cop, is 3.2. it is estimated that the kitchen, bath, and other ventilating fans of the house discharge a houseful of conditioned air once every hour. if the average outdoor temperature is 32â°c, the density of air is 1.20 kg/m3, and the unit cost of electricity is $0.10/kwh, the amount of money "vented out" by the fans in 10 hours is
(a) $0.50
(b) $1.60
(c) $5.00
(d) $11.00
(e) $16.00

The amount that is "vented" out by "the fans" is $0.50 for 10 hours.

Option: a

Explanation:

"Energy discharged by air in every hour" can be determined by,

Q = heat energy (Joules, J)  

m = mass of a substance (kg)  

c = specific heat (units J/kg∙K)  

∆T = 10 hours

Q = 576 × 1.00 × 10

Q = 5760 kJ/hours

W = 1.6 kwh

We know that, “Coefficient of performance” (COP)

Given that, COP = 3.2

W = 0.5 kwh

The unit cost of electricity is $0.10/kWh

The unit cost of electricity is $0.10/kWh

Unit electricity cost for 10 hours = 0.5 × 10 × 0.1$

Unit electricity cost for 10 hours = $0.5

The amount that is "vented out" by "the fans" is $0.50 for 10 hours.

they should be similar or the same

the answer for apex is the lowest