An object of mass 9.00 kg attached to an ideal massless spring is pulled with a steady horizontal force across a frictionless level surface. if the spring constant is 95.0 n/m and the spring is stretched by 10.0 cm , what is the magnitude of the acceleration of the object?

Acceleration of the object will be

Explanation:

We have given mass of the object m = 9 kg

spring constant k = 95 N/m

Spring is stretched by 10 cm

So x = 10 cm = 0.1 m

We know that force is given by

From newton's law we also know that force is given by

F = ma , here m is mass and a is acceleration

So

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explanation:

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2