The small slider of mass m = 0.73 kg is released from rest while in position a and then slides along the vertical-plane track. the track is smooth from a to d and rough (coefficient of kinetic friction μk = 0.26) from point d on. determine (a) the normal force nb exerted by the track on the slider just after it passes point b, (b) the normal force nc exerted by the track on the slider as it passes the bottom point c, and (c) the distance s traveled along the incline past point d before the slider stops. the distance r = 1.10 m.

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A. to determine if humans can explore mars safely

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j