If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it will oscillate. if it is displaced a distance 0.125m from its equilibrium position and released with zero initial speed. then after a time 0.800s its displacement is found to be a distance 0.125m on the opposite side, and it has passed the equilibrium position once during this interval. find : amplitude, period, and frequency.

Explanation:

An object is attached to the spring and then released. It begins to oscillate. If it is displaced a distance 0.125 m from its equilibrium position and released with zero initial speed. The amplitude of a wave is the maximum displacement of the particle. So, its amplitude is 0.125 m.  

After 0.800 seconds, its displacement is found to be a distance 0.125 m on the opposite side. The time period will be,

We know that the relation between the time period and the time period is given by :

f = 0.625 Hz

So, the frequency of the object is 0.625 Hz. Hence, this is the required solution.