Abox slides with uniform acceleration up an incline. the box has an initial speed of 9.0 m/s and rises vertically 2.60 m before coming to rest. if the angle of the incline is 30°, what is the coefficient of kinetic friction between the box and the incline?

0.58

Explanation:

First we need to get the acceleration of the body using equation of motion

v²=u²-2as

v is the final velocity

u is the initial velocity

a is acceleration

s is the distance moved

0²=9²-2a(2.6)

-81=-5.2a

a=81/5.2

a= 15.6m/s²

Angle of inclination =30°

To get the coefficient of friction, we use the formula

Ff =nR

Ff is frictional force

n is coefficient of friction

R is normal reaction

n = Ff/R = Wsin30°/Wcos30°

n = tan30°

n = 0.58

1/0.14nm = 10^10/1.4 a lot

the answer is a. hope this .