When you drink cold water, your body must expend metabolic energy in order to maintain normal body temperature (37â° c) by warming up the water in your stomach. could drinking ice water, then, substitute for exercise as a way to "burn calories? " suppose you expend 286 kilocalories during a brisk hour-long walk. how many liters of ice water (0â° c) would you have to drink in order to use up 286 kilocalories of metabolic energy? for comparison, the stomach can hold about 1 liter.

Explanation:

Given:

Initial temperature of water,  

final temperature of water,

energy spent in one hour of walk,

volumetric capacity of stomach,

Now, let m be the mass of water at zero degree Celsius to be drank to spend 286 kilo-calories of energy.

.....................................(1)

where:

m = mass of water

Q = heat energy

= temperature difference

Putting values in the eq. (1):

Since water has a density of 1 kilogram per liter, therefore the volume of water will be:

the expression 15n + 2(3p) represents the amount isaiah spent buying gasoline and snacks, where n represents the price of each gallon of gasoline and p represents the cost of each snack that he bought. which statement is true about the amount isaiah spent?

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered