When you drink cold water, your body must expend metabolic energy in order to maintain normal body temperature (37â° c) by warming up the water in your stomach. could drinking ice water, then, substitute for exercise as a way to "burn calories? " suppose you expend 286 kilocalories during a brisk hour-long walk. how many liters of ice water (0â° c) would you have to drink in order to use up 286 kilocalories of metabolic energy? for comparison, the stomach can hold about 1 liter.

Explanation:

Given:

Initial temperature of water,  

final temperature of water,

energy spent in one hour of walk,

volumetric capacity of stomach,

Now, let m be the mass of water at zero degree Celsius to be drank to spend 286 kilo-calories of energy.

.....................................(1)

where:

m = mass of water

Q = heat energy

= temperature difference

Putting values in the eq. (1):

Since water has a density of 1 kilogram per liter, therefore the volume of water will be:

wavelength divides in half and speed stays the same.

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is