Physics, 26.11.2019 03:31 mariaf0203
A3.00-m rod is pivoted about its left end. a force of 7.80 n is applied perpendicular to the rod at a distance of 1.60 m from the pivot causing a ccw torque, and a force of 2.60 n is applied at the end of the rod 3.00 m from the pivot. the 2.60-n force is at an angle of 30.0o to the rod and causes a cw torque. what is the net torque about the pivot? (take ccw as positive.)
a. 26.4 nĀ·m
b. 4.68 nĀ·m
c. 8.58 nĀ·m
d. -8.58 nĀ·m
e. -16.4 nĀ·m
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