In 1985 in san antonio, texas, an entire hotel building was moved several
blocks on 36 dollies. the mass of the building was about 1.45 x 10^6 kg. if
1.00 x 10² mj of work was done to overcome the force of resistance that
was just 2.00 percent of the buildings weight, how far was the building
moved?

The building was moved to a distance of, S = 510.2 m

Explanation:

Given data,

The mass of the building, m = 1.45 x 10⁶ kg

The work done to overcome the force of resistance, E = 1 x 10⁸ J

The force of resistance of the building, 2% of building weight

                                          Fₓ =  2 x 1.45 x 10⁶ x 9.8 / 100

                                               = 284200 N

The work done on the building,

                                    E = Fₓ · S

∴                                   S = E /  Fₓ

                                        = 1.45 x 10⁶ / 284200 N

                                        = 510.2 m

Hence, the building was moved to a distance of, S = 510.2 m

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.