How fast does a 3 kg rocket accelerate if a force of 140 n is applied?

46.67 m/s²

Explanation:

We are given;

Mass of a rocket = 3 kg Force applied = 140 N

we are supposed to calculate the acceleration of the rocket;

We are going to use the second Newton's law of motion;According to Newton's second Law of motion force is equivalent to the product of mass and acceleration.This is from the fact that the resultant force and the rate of change in linear momentum are directly proportional.

Therefore;

F = Ma

In this case;

Rearranging the formula

a = F ÷ m

  = 140 N ÷ 3 kg

  = 46.67 m/s²

Thus, the acceleration of the rocket is 46.67 m/s²