An antitank weapon fires a 3.00-kg rocket which acquires a speed of 50.0 m/s after traveling 90.0 cm down a launching tube. assuming the rocket was accelerated uniformly, what is the average force that acted on it?

Force in the rocket will be 4166.64 N

Explanation:

We have given mass of the rocket m = 3 kg

Rocket acquires a speed of 50 m sec so final speed v = 50 m/sec

Initial speed u = 0 m/sec

Distance traveled s = 90 cm = 0.9 m

From third equation of motion we know that

From newton's law we F = ma

So force will be

So force in the rocket will be 4166.64 N

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j