An ornament of mass 40.0 g is attached to a vertical ideal spring with a force constant (spring constant) of 20.0 n/m. the ornament is then lowered very slowly stops stretching. how much does the spring stretch? a) 0.00200 m. b) 0.0196 m. c) 0.0816 m. d) 0.800 m. e) 0.200 m.

Option A is the correct answer.

Explanation:

We have force is the product of spring constant and distance stretched by spring.

             Force = Spring constant x Distance stretched by spring

                F = kx

Force = Mass x acceleration

Mass = 40 g = 0.04 kg

Acceleration = 9.81 m/s²

Force = Mass x acceleration = 0.3924 N

              F = kx

             0.3924 = 20x

                x = 0.0196 m

Option A is the correct answer.

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.