Aman carries a 12-kg chair up one flight of stairs to the second floor of his house. if the second floor is 3.3 m above the first floor, what is the change in the gravitational potential energy of the chair? a - 180 j b + 390 j c + 180 j d - 390 j e zero

Change in gravitational potential energy of the chair is,

Explanation:

It is given that,

Mass of the chair, m = 12 kg

Distance of the second floor from the ground, h = 3.3 m

The position of ground at h = 0

Let is the change in gravitational potential energy of the chair. Initial potential f the chair is equal to 0.

or

So, the change in the gravitational potential energy of the chair is 390 joules.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg