Aparent pushes a balanced frictionless playground merry-go-round. the parent exerts a force f tangent to the merry-go-round resulting in a torque of 240 n . m, the distance between the center of the merry-go-round and the point of application of the force is 1.6 m. (b) what, if any, is the magnitude of the horizontal force exerted by the merry-go-round on the man?

F = 150 N

Explanation:

Torque being applied by parent

= F  x r

where F is force applied tangentially and r is point of application of force from axis of rotation ( center )

given torque = 240 Nm

r = 1.6 m

F x r = 240

F x 1.6 = 240

F = 150 N

So a force of 150 N is applied by the parent to achieve the given torque.

This force will also be applied by the merry - go- around  on the parent as reaction force according to Newton's third law. The parent will not be pushed back by this force  because he is standing on a rough surface . Friction of surface will help him remain stationary on the ground.

u can delete ur account.

1. go on google and write

2 open this and click on your profile pic and if your profile is not appearing, then u have to log in.

3. when u click on your profile pic, there appears four options on the top.

4. click on the 1st option and scroll down and go at the bottom.

5. click on edit profile.

6. there appears a option 'prefernces' and at that option at the right side , 'edit' is written.

7. click on the edit option.

8. there is a option " i want to delete my account" and click on that.

hope this u

and ur welcm

: )