Astudent makes a short electromagnet by winding 580 turns of wire around a wooden cylinder of diameter d = 2.1 cm. the coil is connected to a battery producing a current of 5.1 a in the wire. (a) what is the magnitude of the magnetic dipole moment of this device? (b) at what axial distance z > > d will the magnetic field have the magnitude 4.1 µt (approximately one-tenth that of earth's magnetic field)?

1.02453 Am²

0.36834 m

Explanation:

N = Number of turns = 580

d = Diameter = 2.1 cm

r = Radius =

A = Area =

I = Current = 5.1 A

B = Magnetic field = 4.1 μT

x = Distance

= Vacuum permeability =

Magnetic dipole moment is given by

The magnitude of the magnetic dipole moment of this device is 1.02453 Am²

Magnetic field is given by

The axial distance is 0.36834 m

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