The force required to stretch a hooke’s-law spring varies from 0 n to 43.2 n as we stretch the spring by moving one end 14.4 cm from its unstressed position. find the force constant of the spring. answer in units of n/m.

Spring constant = 300 N/m

Explanation:

For a spring we have force is the product of spring constant and displacement.

          Force = Spring constant x Displacement

          F = k x

Here Force , F = 43.2 - 0 = 43.2 N

         Displacement, x = 14.4 cm = 0.144 m

Substituting

              F = k x

              43.2 = k x 0.144

               k= 300 N/m

Spring constant = 300 N/m

pe = weightxheight = 2000x1000=2,000,000joules

laticia draws the diagram below to show earth’s magnetic field.

answer

the arrows to the right of earth should point up.