If a rainstorm drops 5 cm of rain over an area of 13 km2 in the period of 3 hours, what is the momentum (in kg · m/s) of the rain that falls in five seconds? assume the terminal velocity of a raindrop is 10 m/s. (enter the magnitude. the density of water is 1,000 kg/m3.)

To solve the problem it is necessary to apply the concepts related to Conservation of linear Moment.

The expression that defines the linear momentum is expressed as

P=mv

Where,

m=mass

v= velocity

According to our data we have to

v=10m/s

d=0.05m

Volume

t = 3hours=10800s

From the given data we can calculate the volume of rain for 5 seconds

Where,

It is the period of time we want to calculate total rainfall, that is

Through water density we can now calculate the mass that fell during the 5 seconds:

Now applying the prevailing equation given we have to

Therefore the momentum of the rain that falls in five seconds is

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explanation:

this would be about 43%