After a recent storm, one of the traffic lights in city town, usa was damaged. without this light back and working, the villagers of city town cannot safely travel to get their favorite in-n-out burgers for lunch. can you them? the traffic light has weight 246 n. assume that all lines connected to the traffic light are in tension and are straight lines. point o is the origin, having coordinates (0,0,0).: given coordinates for a, b, c and d, x a = -10 m y a = 5 m z a = 8 m x b = -10 m y b = 6 m z b = -5 m x c = 15 m y c = 10 m z c = 0 m x d = -10 m y d = -2 m z d = 3 m

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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It is either a  proton or a neutron im almost positive. hope this .