Determine the minimum gauge pressure needed in the water pipe leading into a building if water is to come out of a faucet on the twelfth floor, 45 m above that pipe. express your answer using two significant figures.

P(gauge) =  450 KPa

Explanation:

Given that

h= 45 m

We know that ,density of water ρ = 1000 kg/m³

The acceleration due to gravity g = 10 m/s²

As we know that pressure above the atmospheric pressure is known as gauge pressure.And the summation of gauge and atmospheric pressure is known as absolute pressure.

The gauge pressure P(gauge) given as

P(gauge) =  ρ g h

Now by putting the values

P(gauge) =  ρ g h

P(gauge) =  1000 x 10 x 45 Pa

P(gauge) =  450 KPa

c

explanation:

v=ir = 3x15 =45 v