A1.60 kg , horizontal, uniform tray is attached to a vertical ideal spring of force constant 200 n/m and a 285 g metal ball is in the tray. the spring is below the tray, so it can oscillate up-and-down. the tray is then pushed down 14.8 cm below its equilibrium point (call this point a) and released from rest.

The height is 24.03 cm.

Explanation:

Given that,

Mass = 1.60 kg

Force constant = 200 N/m

Mass of metal ball = 285 g

Distance x= 14.8 cm

Suppose How high above point A will the tray be when the metal ball leaves the tray?

The force exerted by the spring in the downward

...(I)

The downward force is

...(II)

From equation (I) and (II)

Put the value into the formula

The point here is 9.23 cm above the equilibrium point and therefore the high above point A is

Hence, The height is 24.03 cm.

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explanation: