Which will most likely increase the kinetic energy in this
system?
pulling farther back on the string
releasing the string
holding the arrow higher
decreasing the mass of the arrow

releasing the string

Explanation:

In a bow-arrow system, the potential energy stored by pulling the string backwards gets converted to kinetic energy when the string is released. Thus, more the string is pulled backwards, more potential energy would be stored. When the string is released, the potential energy reduces and converts to kinetic energy. Therefore, by releasing the string, the kinetic energy increases

releasing the string

Explanation:

In a bow-arrow system, the potential energy stored by pulling the string backwards gets converted to kinetic energy when the string is released. Thus, more the string is pulled backwards, more potential energy would be stored. When the string is released, the potential energy reduces and converts to kinetic energy. Therefore, by releasing the string, the kinetic energy increase

I hope this work

like poles repel so keep pushing north to north and repels funny to see this

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.