A3.0-cm-diameter tube is held upright and filled to the top with mercury. the mercury pressure at the bottom of the tube − the pressure in excess of atmospheric pressure-is 48 kpa. how tall is the tube?

Given a tube of diameter d, = 3cm = 0.03m

Pressure Balance

Mercury pressure at the tube bottom Pₓ = Pa + ρgh

where

Pa = Atmospheric pressure = 101kpa

ρ = Density of mercury = 13,546kg/m3

g = acceleration due to gravity

h = height of the tube?

Given

Bottom pressure in excess of the atmospheric pressure = 48kPa = Pₓ - Pa

Therefore, 48kPa = ρgh

h = 48(kN/m2)/ρg

h = 48,000kgms⁻²m⁻²/(13546kgm⁻³ x 9.81ms⁻²)

h = 0.36m

the tube is 36cm tall

3

step-by-step explanation:

10 - 2.8 = 7.2

2 2/5 = 2.4

7.2 / 2.4 = 3

as technology advances, new experiments often expose problems in accepted theories. c

hope i

-lavira: )