Consider a steel guitar string of initial length l=1.00 meter and cross-sectional area a=0.500 square millimeters. the young's modulus of the steel is y=2.0×10¹¹ pascals. how far ( δl) would such a string stretch under a tension of 1500 newtons? use two significant figures in your answer. express your answer in millimeters.

Explanation:

Given:

We have the relation for change in length:

like poles repel so keep pushing north to north and repels funny to see this

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .