How much will the temperature of a 250 g block of silver increase if 2000 cal of heat is added to it?

143.37 K or °C

We are given;

We are required to determine change in temperature for the block of ice.

Q = m × c × ΔT, where M is the mass of an object, c is the specific heat capacity and ΔT is the change in temperature.

In this case;

Q = 2000 calories

Mass = 250 g

specific heat , c of silver is 0.0558 cal/g°C

Therefore;

Rearranging the formula;

ΔT = Q ÷ mc

    = 2000 cal ÷ (250 g × 0.0558 cal/g°C)

    = 143.37 °C or K

The change in temperature is 143.37 K or °C

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

he . if i may ask what i your question exactly?

explanation: