Starting from rest, a horse pulls a 263−kg cart for a distance of 1.6 km. it reaches a speed of 0.38 m/s by the time it has walked 50.0 m and then walks at constant speed. the frictional force on the rolling cart is a constant 253 n. each gram of oats the horse eats releases 9 kj of energy; 10 % of this energy can go into the work the horse must do to pull the cart. how many grams of oats must the horse eat to pull the cart?

Explanation:

The work done on the cart by the horse is found by:

replacing:

, , , ,

10% E= 900J

Hey can someone me with my homework

The answer is water molecules are split.cellular respiration and photosynthesis are complement  reactions to each other. these are reverse reactions. in cellular respiration glucose and oxygen yield water and carbon dioxide. so, when respiration begins,  glucose molecules are split. in the opposite reaction - in photosynthesis, carbon dioxide and water yield glucose and oxygen. thus,  when respiration begins, water molecules are split.