Aperson with his ear to the ground, sees a huge stone strikethe concrete pavement. a moment later two sounds are heard from theimpact: one travels n the air and the other in the concrete, andthey are 2.2 s apart. how far away did the impact occur?
*the speed of sound for air is 343 m/s, for concrete˜3000.

d= 852.01 m

Explanation:

Given that

Speed of sound in air u= 343 m/s

Speed of sound in concrete v= 3000  m/s

Lets take time taken by sound in the concrete is t then the time taken by sound in air will be t+2.2 s  .

The distance (d)travel will be same in both the cases.

We know that

Distance =  Velocity x time

So

d= 3000 x t  = 343 x (t+2.2)

3000 t = 343 t + 343 x 2.2

t= 0.284 s

So the distance d

d= 3000 x 0.284 m

d= 852.01 m

where is the circuit diagram ?