If a marble is released from a height of 1955 cm, how long would it take to hit the ground?

1.997s = 2.0s

Explanation:

From equation of motion,

S = ut + 1/2 gt²

u = 0 m/s

t = ?

g = 9.8 m/s²

S = 1955cm = 19.55m

19.55 = 0 + 1/2 * 9.8 * t²

19.55 * 2 = 9.8t²

t² = 19.55 * 2 / 9.8

t² = 3.987

t = (3.987)^½ (take the square root of both sides)

t = 1.997s = 2.0s

answer would be d.) i hope this

explanation:

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.