Asmall object has a mass of 2.9 10-3 kg and a charge of -36 µc. it is placed at a certain spot where there is an electric field. when released, the object experiences an acceleration of 2.49 103 m/s2 in the direction of the +x axis. determine the magnitude and direction of the electric field.

200583.33 N/C direction opposite to that of the acceleration

Explanation:

m = Mass of object =

a = Acceleration of the object =

q = Charge =

E = Electric field

Here the inertia of the object will balance the electric force

The magnitude of the electric field is 200583.33 N/C and the direction is opposite to that of the acceleration.

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