On a frozen pond, a 10.3 kg sled is given a kick that imparts to it an initial speed of vo = 1.64 m/s. the coefficient of kinetic friction between sled and ice is mk = 0.128. use the work kinetic energy theorem to find the distance the sled moves before coming to rest.

d=1.07m

Explanation:

Calculate Initial Kinetic Energy:

KE = 1/2*m*v^2

KE= 0.5*(10.3kg)*(1.64m/s)^2 = 13.85J

Calculate work overcoming friction:

W = F*d = mu*m*g*d

W = (0.128)*(10.3kg)*9.80m/s^2)*d

W = 12.92*d

Equate the two since all of the kinetic energy is used up in working against friction:

W = KE

12.92d = 13.851J

Solve for d:

d= (13.851J)/(12.92) = 1.07 m

the correct choice is a .

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