If the acceleration of the block in the diagram below is 5.00 m/s, what is the coefficient of kinetic friction?
20.0 kg
60.0°

0.712

Explanation:

Forces are acting on the block according to the diagram attached , where

By definition

Fr = μ*R

   = μ*mg *cos(60) ----------(1)

where μ -coefficient of kinetic friction

Applying F = ma along the incline (Assume g = 9.8 ms⁻²)

F = ma

mg * sin(60) - Fr = ma

mg*sin(60) - μ*mg *cos(60) = ma

9.8 * sin(60) - μ*9.8*cos(60) = 5

μ = 0.712

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