Calculate the rate of heat conduction out of the human body, assuming that the core internal temperature is 37.0°c, the skin temperature is 32.8°c, the thickness of the tissues between averages 1.00 cm, and the surface area is 1.90 m2. the conductivity of tissue is 0.20 j/(s · m · °c).

The rate of heat conduction out of the human body is: 159.6(J/s)

Explanation:

We need to apply the thermal conduction equation (), where Q is heat, t is time, K is the thermal conductivity constant of the material, A is the surface area of transfer heat, T is temperature and L is the distance of the "wall" between the differents temperatures (see attached), it's used because the tissues are in direct contact between them. Now we need to know that Q/t is the rate of heat conduction so replacing the values given, we get: , the negative sign means the heat is outing of the body, so the rate of heat conduction out of the human body will be: 159.6(J/s).

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray

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isoceles right angled triangle