part one:
a force f~ = fx ˆı + fy ˆ acts on a particle that

undergoes a displacement of ~s = sx ˆı + sy ˆ

where fx = 1 n, fy = −4 n, sx = 1 m, and

sy = 2 m.

find the work done by the force on the

particle.

answer in units of j.

part two:
find the angle between f~ and ~s.
answer in units of ◦

Sorry i don’t know what to do

Ray 2 should cross through the focal point on the right side of the lens

To compare speeds speeds of wagons we will use second newton's law. it states: f = m * ahere we can see that force depends on the acceleration. if we know acceleration for both wagons we can compare them to make conclusion of speeds of wagons.we have: m1 = 10lbm2 = 20lbf1 = 2*f2also: m2 = 2*m1for bill we have equation: f1 = m1 * a1for tom we have equation: f2 = m2 * a2after inserting identities we have: 2*f2 =m1 * a1f2 = 2*m1 * a2in order to make conclusions about speeds we will solve these equations for a and find their ratio: a1 = 2f2 / m1a2 = f2 / 2m1a1 / a2 = (2f2/m1) / (f2/2m1)a1 / a2 = (2f2*2m1) / (m1*f2)a1 / a2 = (4f2m1) / (m1f2)a1 / a2 = 4this ratio is bigger than 1 and this means that a1 is greater than a2. a1 is 4 times greater than a2. speed of bill's wagon is 4 times greater than speed of tom's wagon.