Suppose a 1.95 t field is applied across a 10-gauge copper wire (2.588 mm in diameter) carrying a 20.5 a current. what would the hall voltage be, in microvolts, if the number density of free electrons in copper is 8.34 × 1028m-3?

1.47 microvolts

Explanation:

B = Magnetic field = 1.95 T

I = Current in wire = 20.5 A

n = Number density of free electrons in copper =

D = Diameter of wire = 2.588 mm

A = Area =

e = Charge of electron =

Hall voltage is given by

The Hall voltage is 1.47 microvolts

increases it

be subject to a force andchange its motion