Two particles with masses m and 3m are moving toward each other along the x axis with the same initial speeds vi. particle m is traveling to the left, and the particle 3m is traveling to the right. they undergo an elastic glancing collision such that particles m is moving in the negative y direction after the collision at a right angle from its initial direction.

(a) find the final speeds of the two particles in terms of vi.

(b) what is the angle theta at which the particle 3m is scattered?

ANGLE is 35.3 degree celcius

Explanation:

Given data:

mass m and 3m

initial speed Vi

particle with mass m is moving toward left while particle with mass 3m is moving toward right

By using conservation of momentum :

conservation of energy :

After collision, particle with mass m moves at right angles, thus by considering conservation of momentum in x & y direction,

x direction :

y direction :

subsitute these value in energy conservation

35.3 degree from x-axis

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.